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For 2 number x1 and x2:

*x*_{1} = *a*_{1} × 10^{b1}

*x*_{2} = *a*_{2} × 10^{b2}

*x*_{1} +
*x*_{2}
= *a*_{1} × 10^{b1} + *a*_{2} × 10^{b2}

*x*_{1} - *x*_{2}
= *a*_{1} × 10^{b1} - *a*_{2} × 10^{b2}

*x*_{1} × *x*_{2}
= *a*_{1}*a*_{2} × 10^{b1+b2}

*x*_{1} / *x*_{2}
= (*a*_{1}/*a*_{2}) × 10^{b1-b2}

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Users write Now: ivan kitaev • 2 years ago Are you serious? must be considered first with multiplication!Eugene Tkachenko

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